Yarninator/bgg_api
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Fixed wrong variable naming

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This commit is contained in:
Yarne Coppens 2024-08-15 11:21:33 +02:00
parent 6992b1a6b3
commit 427a482b7c
1 changed files with 4 additions and 4 deletions
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8
src/main.py
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@ -128,7 +128,7 @@ def get_amount_of_games(query: BoardgameFilterParams = Depends(), session: Sessi
owned_collection = data_connection.get_user_owned_collection(session) owned_collection = data_connection.get_user_owned_collection(session)
to_return_boardgames = query.do_filtering(to_return_boardgames) owned_collection = query.do_filtering(owned_collection)
statistic_dict = { statistic_dict = {
"name":"Amount of games in owned collection", "name":"Amount of games in owned collection",
@ -152,7 +152,7 @@ def get_amount_of_games_over_time(query: BoardgameFilterParams = Depends(), day_
start_date = games_in_owned_collection[0].acquisition_date start_date = games_in_owned_collection[0].acquisition_date
to_return_boardgames = query.do_filtering(to_return_boardgames) games_in_owned_collection = query.do_filtering(games_in_owned_collection)
timeline_dict = {} timeline_dict = {}
@ -175,7 +175,7 @@ def get_amount_of_games_played_per_year(query: BoardgameFilterParams = Depends()
all_plays.sort(key= lambda x: x.play_date) all_plays.sort(key= lambda x: x.play_date)
to_return_boardgames = query.do_filtering(to_return_boardgames) all_plays = query.do_filtering(all_plays)
all_played_boardgame_ids = [] all_played_boardgame_ids = []
@ -209,7 +209,7 @@ def get_most_expensive_game(query: BoardgameFilterParams = Depends(), top_amount
most_expensive_games: list[Union[boardgame_classes.OwnedBoardGame, boardgame_classes.OwnedBoardGameExpansion]] = data_connection.get_user_owned_collection(session) most_expensive_games: list[Union[boardgame_classes.OwnedBoardGame, boardgame_classes.OwnedBoardGameExpansion]] = data_connection.get_user_owned_collection(session)
to_return_boardgames = query.do_filtering(to_return_boardgames) most_expensive_games = query.do_filtering(most_expensive_games)
most_expensive_games.sort(key=lambda x: x.price_paid, reverse=True) most_expensive_games.sort(key=lambda x: x.price_paid, reverse=True)